The correct option is D: $ 5(3+ x)-2x(3+x)$ We have $(5 - 2x) (3 + x)$ $=5(3+ x)-2x(3+x)$ [Multiplying two binomials] Was this answer helpful? 0. Similar Questions. Q1. Algebra. Graph y=2x+4. y = 2x + 4 y = 2 x + 4. Use the slope-intercept form to find the slope and y-intercept. Tap for more steps Slope: 2 2. y-intercept: (0,4) ( 0, 4) Any line can be graphed using two points. Select two x x values, and plug them into the equation to find the corresponding y y values. Algebra. Write in Slope-Intercept Form y-5=3 (x-2) y − 5 = 3(x − 2) y - 5 = 3 ( x - 2) The slope-intercept form is y = mx+ b y = m x + b, where m m is the slope and b b is the y-intercept. y = mx +b y = m x + b. Rewrite in slope-intercept form. Tap for more steps y = 3x− 1 y = 3 x - 1. Free math problem solver answers your algebra 0.53. 2x2 + 16x + 24. 252 −16558. (38) = 56− 14. 32 − 5x = bx + 31. (4828 + 5024.5 48+52x) × 0.1 + 108 × 0.15 + 3015 × 0.75 = 0.5. 3 − 3y = −4 Solve for z where z = −2y. loge 2. y = −2x2 −8x +9. This function has two x-intercepts at ±3 and one y-intercept at y=5. By swapping the x- and y-variables, we can get an equation for the graph you want: x = -(5/3)|y| +5 _____ Comment on this answer. Since there are no requirements on the graph other than it have the listed intercepts, you can draw it free-hand through the intercept points. Answer link. f^-1 (x)=root (3) (-1/2 (x-5)) f (x)=y y=5-2x^3 Switch the places of x and y: x=5-2y^3 Now, solve for y: x-5=-2y^3 y^3=-1/2 (x-5) Take the cube root of both sides: root (3)y=root (3) (-1/2 (x-5)) y=root (3) (-1/2 (x-5)) Now that we have solved for y after switching the places of x and y, y=f^-1 (x) f^-1 (x)=root (3) (-1/2 (x-5)) zmECbhz. SolutionStep 1: Simplify the term algebraic equations which are valid for all values of variables in them are called algebraic identities. They are also used for the factorization of the algebraic identity a-b3=a3-b3-3aba-b to simplify the expression 2x-5y3:2x-5y3=2x3-5y3-32x5y2x-5y=8x3-125y3-30xy2x-5y=8x3-125y3-60x2y+150xy2∴2x-5y3=8x3-125y3-60x2y+150xy2Step 2: Simplify the term 2x+ the algebraic identity a+b3=a3+b3+3aba+b to simplify the expression 2x+5y3:2x+5y3=2x3+5y3+32x5y2x+5y=8x3+125y3+30xy2x+5y=8x3+125y3+60x2y+150xy2∴2x+5y3=8xStep 3: Simplify the given expression 2x-5y3-2x+5y3:Use the results obtained in Steps 1 and 2 to simplify the expression 2x-5y3-2x+5y3:2x-5y3-2x+5y3=8x3-125y3-60x2y+150xy2-8x3+125y3+60x2y+150xy2=8x3-125y3-60x2y+150xy2-8x3-125y3-60x2y-150xy2=8x3-8x3-125y3-125y3-60x2y-60x2y+150xy2-150xy2=-250y3-120x2yHence, 2x-5y3-2x+5y3= Corrections3 Ta metoda polega na dodawaniu równań stronami, w sytuacji gdy przy tej samej niewiadomej w dwóch równaniach mamy przeciwne współczynniki. Rozwiąż układ równań metodą przeciwnych współczynników: \[ \begin{cases} x+2y=8\\ 2x-y=1 \end{cases} \]Na początku drugie równanie pomnożymy stronami przez \(2\): \[ \begin{cases} x+2y=8\\ 4x-2y=2 \end{cases} \] Dzięki temu, przy niewiadomej \(y\) otrzymaliśmy przeciwne współczynniki (w pierwszym równaniu \(2\), a w drugim \(-2\)). Możemy teraz dodać równania stronami, otrzymując równanie: \[\begin{split} x+4x+2y-2y&=8+2\\[6pt] 5x&=10\\[6pt] x&=2 \end{split}\] Teraz z dowolnego równania (np. \(x+2y=8\)) wyliczamy \(y\), podstawiając pod \(x\) znaną wartość: \[ \begin{split} 2+2y&=8\\[6pt] 2y&=6\\[6pt] y&=3 \end{split} \] Czyli rozwiązaniem układu równań jest para liczb: \[\begin{cases} x=2\\ y=3 \end{cases} \] Rozwiąż układ równań \(\begin{cases} x+3y=5\\ 2x-y=3 \end{cases} \).\(\begin{cases} x=2 \\ y=1 \end{cases} \) Algebra Examples Step 1Use the slope-intercept form to find the slope and slope-intercept form is , where is the slope and is the the values of and using the form .The slope of the line is the value of , and the y-intercept is the value of .Slope: y-intercept: Step 2Any line can be graphed using two points. Select two values, and plug them into the equation to find the corresponding a table of the and 3Graph the line using the slope and the y-intercept, or the y-intercept: Algebra Examples Step 2Use the slope-intercept form to find the slope and slope-intercept form is , where is the slope and is the the values of and using the form .The slope of the line is the value of , and the y-intercept is the value of .Slope: y-intercept: Step 3Any line can be graphed using two points. Select two values, and plug them into the equation to find the corresponding a table of the and 4Graph the line using the slope and the y-intercept, or the y-intercept: Solution: Given, the polynomial is 4x² + 5√2x - 3. We have to find the relation between the coefficients and zeros of the polynomial Let 4x² + 5√2x - 3 = 0 On factoring, = 4x² + 6√2x - √2x - 3 = 2√2x(√2x + 3) - (√2x + 3) = (2√2x - 1)(√2x + 3) Now, 2√2x - 1 = 0 2√2x = 1 x = 1/2√2 Also, √2x + 3 = 0 √2x = -3 x = -3/√2 Therefore,the zeros of the polynomial are 1/2√2 and -3/√2. We know that, if 𝛼 and ꞵ are the zeroes of a polynomial ax² + bx + c, then Sum of the roots is 𝛼 + ꞵ = -coefficient of x/coefficient of x² = -b/a Product of the roots is 𝛼ꞵ = constant term/coefficient of x² = c/a From the given polynomial, coefficient of x = 5√2 Coefficient of x² = 4 Constant term = -3 Sum of the roots: LHS: 𝛼 + ꞵ = 1/2√2 - 3/√2 = (1-6)/2√2 = -5/2√2 = -5√2/4 RHS: -coefficient of x/coefficient of x² = -5√2/4 LHS = RHS Product of the roots LHS: 𝛼ꞵ = (-3/√2)(1/2√2) = -3/4 RHS: constant term/coefficient of x² = -3/4 LHS = RHS Therefore, the zeroes of the polynomial are -3/√2 and 1/2√2. The relation between the coefficients and zeros of the polynomial are, Sum of the roots = -b/a = -5√2/4, Product of the roots = c/a = -¾. ✦ Try This: Find the zeroes of the polynomial 4x² + 3√2x - 8, and verify the relation between the coefficients and the zeroes of the polynomial ☛ Also Check: NCERT Solutions for Class 10 Maths Chapter 2 NCERT Exemplar Class 10 Maths Exercise Problem 6 4x² + 5√2x - 3. Find the zeroes of the polynomial, and verify the relation between the coefficients and the zeroes of the polynomial Summary: The zeroes of the polynomial 4x² + 5√2x - 3 are -3/√2 and 1/2√2. The relation between the coefficients and zeros of the polynomial are, Sum of the roots = -b/a = -5√2/4, Product of the roots = c/a = -¾ ☛ Related Questions: v² + 4√3v - 15. Find the zeroes of the polynomial, and verify the relation between the coefficients . . . . y² + (3√5/2)y - 5. Find the zeroes of the polynomial, and verify the relation between the coefficien . . . . 7y² - (11/3)y - (2/3). Find the zeroes of the polynomial , and verify the relation between the coeff . . . .

y 5 2x 3